Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.        

                

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.        

                

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.        

                

Sample Input

2

1 2

112233445566778899 998877665544332211

                

Sample Output

Case 1: 1 + 2 = 3 Case 2: 112233445566778899 + 998877665544332211 = 1111111111111111110

 

 

#include
         
          #include
          
           #include
           
            #include
            
             using namespace std;int f(char a[],char b[],int s[]){    int m=strlen(a),n=strlen(b),i,x[1005],y[1005],k;    memset(x,0,sizeof(x));    memset(y,0,sizeof(y));    k=max(m,n);    if(m==k){        for(i=0;i
             
              =m-n;i--)y[i]=b[n-m+i]-'0';    }    if(n==k){        for(i=0;i
              
               =n-m;i--)x[i]=a[m-n+i]-'0'; } s[0]=0; for(i=1;i
               
                =0;i--){ if(s[i]>9){ s[i]-=10; s[i-1]++; } } return k;}int main(){ char a[1005],b[1005]; int n,k=1; cin>>n; while(k<=n){ cin>>a>>b; cout<<"Case "<
                
                 <<":"<
                
               
              
             
            
           
          
         

 

 格式错误好几次